Separate the coins into 3 stacks of 9 (A, B, C). Weigh stack A against B and then A against C.
Reasoning Puzzles Questions and Answers with detailed explanation for candidates preparing for banking, Railway, SSC and other competitive examinations. Frequently asked reasoning puzzles questions with solution for bank exams. We provide more puzzles questions on a daily basis for students to improve problem solving skill. Sep 30, 2019 Get TOP 50 Important reasoning PDF Puzzle Questions pdf we have covered all types & the questions for the IBPS RRB PO/Clerk Mains level.
Take the stack with the different weight (note lighter or heavier) and break it into 3 stacks of 3 (D, E, F). Weigh stack D against E.
If D and E are equal, then F is the odd stack. If D and E are not equal, the lighter or heavier (based on the A, B, C comparison) is the odd stack. You now have three coins (G, H, I). Weigh G and H. If G equals H, then I is the odd and is lighter or heavier (based on the A, B, C comparison). If G and H are not equal, then the lighter or heavier (based on the A, B, C comparison) is the odd coin.If you like this type of brain teasers, then surely check out other. There are many easier ones as well.
Hats On A Death RowYou are one of 20 prisoners on death row with the execution date set for tomorrow. Your king is a ruthless man who likes to toy with his people's miseries. He comes to your cell today and tells you:'I'm gonna give you prisoners a chance to go free tomorrow.
You will all stand in a row (queue) before the executioner and we will put a hat on your head, either a red or a black one. Of course you will not be able to see the color of your own hat; you will only be able to see the prisoners in front of you with their hats on; you will not be allowed to look back or communicate together in any way (talking, touching.).The prisoner in the back will be able to see the 19 prisoners in front of him. The one in front of him will be able to see 18.Starting with the last person in the row, the one who can see everybody in front of him, he will be asked a simple question: WHAT IS THE COLOR OF YOUR HAT?He will be only allowed to answer 'BLACK' or 'RED'. If he says anything else you will ALL be executed immediately.If he guesses the right color of the hat on his head he is set free, otherwise he is put to death.
And we move on to the one in front of him and ask him the same question and so on.Well, good luck tomorrow, HA HA HA HA HA HA!' Now since you all can communicate freely during the night, can you find a way to guarantee the freedom of some prisoners tomorrow? The Liar, The Truth Teller and The Random AnswererThere is a truth teller (always tells the truth), a liar (always lies), and one that sometimes answers truthfully and sometimes lies. Each man knows who is who.
You may ask three yes or no question to determine who is who. Each time you ask a question, it must only be directed to one of the men (of your choice). You may ask the same question more than once, but of course it will count towards your total.What are your questions and to whom will you ask them? There are 6 possible states for the order of the men: TRL, TLR, LTR, LRT, RTL, RLTThere are 8 possible combinations of anwers for questions: TTT, TTL, TLT, TLL, LTT, LTL, LLT, LLL.Theoretically it's possbile if you could figure out a way to get any of the 8 combinations of answers assigned to the states, but with the unreliability of Random's answers, I thought it was impossible. There is always a possiblity in any solution where Random will exactly mirror T or L for answers. He could always lie or always tell the truth and you can never tell when he is lying or telling the truth. This being given, I thought you can NEVER separate 6 distinct answers to apply to the 6 states, and therefore can never be sure who is who.After a minute though, I saw through my own error in logic.
I was always dealing with questions where T and L would give the same answer regardless of the order of the men. I saw that if you can get T and L to give a Yes/NO answer, then you can figure out where R's worthless answers are. The only way I saw to do this is to ask about the order of the men themselves.So:Ask #1 if L is standing on R's right arm (our left if they are facing us).The answer gives you a split in the order they are standing:If YES, then it has to be T telling the truth, L telling a lie, or one of R's worthless answers, so: TLR, LTR, or RTL, RLT.If NO, then it has to be T telling the truth, L telling a lie, or R and his worthless answers, so: TRL, LRT, or RTL, RLT.Now we know, based on the answer to #1 where to avoid R's worthless answers. We now ask T or L 'Is T in the lineup?' If answer 1 was Yes, we ask person 2, if it was no we ask person 3.The answer now will give us some more info. If it's Yes, it's T answering the truth, if it's no, it's L answering a lie. So based on who we asked, we now know:Yes, Yes: Has to be LTR, or RTLYes, No: TLR, RLTNo, Yes: LRT, RLTNo, No: TRL, RTLNow any question separating the two possiblities works - just make sure you are avoiding R's worthless answers.For example:Yes, Yes - ask #2 if #1 is L.
(We know #2 is T and will tell the truth) - Yes = LTR, No = RTLYes, No, - ask #2 if #1 is T. ( We know #2 is L and will tell a lie) - Yes = RLT, No = TLRNo, Yes - ask # 3 if #1 is L.
(We know #3 is T and will tell the truth) - Yes = LRT, No = RLTNo, No, - ask #3 if #1 is T. (We know #3 is L and will tell a lie) - Yes = RTL, No = TRLSo we have the order and know who is who.If you like this type of brain teasers, then surely check out other. There are many easier ones as well. Of course, it's not 1/2 else would make it a lousy puzzle.Ans: 1/3This is a famous question in understanding conditional probability, which simply means that given some information you might be able to get a better estimate.The following are possible combinations of two children that form a sample space in any earthly family:Girl - GirlGirl - BoyBoy - GirlBoy - BoySince we know one of the children is a girl, we will drop the Boy-Boy possibility from the sample space.This leaves only three possibilities, one of which is two girls. Hence the probability is 1/3.
Jennifer should switch. Contrary to what may seem intuitive, switching actually doubles her chances of winning the car.This problem is just a re-wording of what is known as the Monty Hall Problem. The key to understanding it is that the host knows the locations of the car and goats.
Any point on the circle (1 + 1/2pi) miles from the South Pole.After going South 1 mile, you're (1/2pi) miles from the Pole,which allows you to run West 1 mile 1 lap of a 1-mile circumference circleand be able to go a mile North to the starting point.There is an infinite number of starting distances:1 + 1/2Npi miles North of the South pole where N is any positive integer.N is then the number of circular laps in your westerly mile.e.g. N=5280 - you'd run 5280 laps around a 1-foot circumference circle. Hole in a SphereA 6-inch hole is drilled through a sphere. What is the volume of the remaining portion of the sphere?Clarifications:1 the hole is a circular cylinder of empty space whose axis passes through the center of the sphere - just as a drill would make if you aimed the center of the drill at the center of the sphere and made sure you drilled all the way through.2 the length of the hole 6 inches is the height of the cylinder that forms the inside surface once the hole is drilled. Picture the inside surface as viewed from inside the hole and measure the length of that surface in the direction of the axis of the drill.in this sense, you could for example drill a 6-inch hole through the earth. The diameter of the hole would be huge, and you'd just have a tiny remnant of the earth left. But if you could set it on a table a big table it would be 6 inches high.You of course could not drill a 6-inch hole through a sphere whose diameter was less than 6 inches.
This fact leads to the logical answer.The hard way involves calculus. The easy way uses logic. A Remainder is Chasing MeI just found a number with an interesting property:When I divide it by 2, the remainder is 1.When I divide it by 3, the remainder is 2.When I divide it by 4, the remainder is 3.When I divide it by 5, the remainder is 4.When I divide it by 6, the remainder is 5.When I divide it by 7, the remainder is 6.When I divide it by 8, the remainder is 7.When I divide it by 9, the remainder is 8.When I divide it by 10, the remainder is 9.It's not a small number, but it's not really big, either.Find the smallest number with such property. Another Oldie - Can You Get Them All?. 26 L of the A.
7 D of the W. 7 W of the W. 12 S of the Z. 66 B of the B. 52 C in a P (W J). 13 S in the U S F.
18 H on a G C. 39 B of the O T. 5 T on a F. 90 D in a R A. 3 B M (S H T R). 32 is the T in D F at which W F. 15 P in a R T.
3 W on a T. 100 C in a D.
11 P in a F (S) T. 12 M in a Y. 13 is U F S. 8 T on an O. 29 D in F in a L Y. 27 B in the N T.
365 D in a Y. 13 L in a B D. 52 W in a Y. 9 L of a C. 60 M in an H. 23 P of C in the H B.
64 S on a C B. 9 P in S A. 6 B to an O in C. 1000 Y in a M. 15 M on a D M C. 26 L of the A - 26 Letters of the Alphabet2. 7 D of the W - 7 days of the Week3.
7 W of the W - 7 wonders of the world4. 12 S of the Z - 12 signs of the zodiac5. 66 B of the B - 66 books of the bible6. 52 C in a P (W J) - 52 cars in a pack (without jokers)7. 13 S in the U S F - 13 stripes in the united states flag8. 18 H on a G C - 18 holes on a golf course9.
39 B of the O T - 39 books of the old testament10. 5 T on a F - 5 toes on a foot11. 90 D in a R A - 90 degrees in a right angel12. 3 B M (S H T R) - 3 blind mice (see how they run)13. 32 is the T in D F at which W F - 32 is the temperature in degrees ferenheight at which water freezes14. 15 P in a R T - 15 players in a rugby team15.
3 W on a T - 3 wheels on a tricycle16. 100 C in a D - 100 cents in a dollar17. 11 P in a F (S) T - 11 players in a football (soccer) team18. 12 M in a Y - 12 months in a year19. 13 is U F S - 13 is unlucky for some20.
8 T on an O - 8 tenticles on an octopus21. 29 D in F in a L Y - 29 days in Feburary in a leap year22. 27 B in the N T - 27 books in the new testiment23. 365 D in a Y - 365 days in a year24. 13 L in a B D - 13 loaves in a baker's dozen25. 52 W in a Y - 52 weeks in a year26.
9 L of a C - 9 lives of a cat27. 60 M in an H - 60 minutes in an hour28. 23 P of C in the H B - 23 pairs of chromosomes in the human body29. 64 S on a C B - 64 squares on checkers board30.
9 P in S A - 9 provinces in south africa31. 6 B to an O in C - 6 bowls to an over in cricket32. 1000 Y in a M - 1000 years in a millenium33. 15 M on a D M C - 15 men on a dead man's chest.
Build logical thinking skills with these addition square puzzles.Challenge students with these mind-bending, critical thinking puzzles.Assemble a cipher disk and use it to decode facts about animals, explorers, plants, and other science/social studies topics.Students love to learn with these foldable origami cootie catcher (aka Fortune Teller) games.This page has a nice selection of 'connect the dots' puzzles. These are great for reviewing basic counting, alphabet, roman numerals, and skip counting.Look carefully for items hidden within the playful scenes.Build vocabulary and critical thinking skills with these analogy worksheets.Penelope Peabody is lost somewhere in the USA. Can you tell where she is? Use the 50 states worksheet puzzles on a daily or weekly basis.First find the answers to the math problems and plug the answers into the puzzles.To find the answer to a funny riddle, solve the math problems. Skills include division, multiplication, subtraction, addition, place value, roman numerals, and many more.Plot the ordered pairs on the coordinate grid and connect the points to reveal mystery pictures.Solve the subtraction, addition, division, and multiplication facts to reveal a mystery picture.The teacher posts a clue each day of the week.
Students read the clues and try to figure out the mystery number.Kids love these math puzzle match games! Try them in your learning centers. Topics include addition, subtraction, multiplication, division, time, money and more!Learn Sudoku with these easy, fun puzzles.Weekly 'What Am I?' Challenge puzzles for kids of all ages.Students change one letter in each word on the puzzle to make a new word. These are great for teaching phonics, vocabulary, and critical thinking.Connect the letters in these maze puzzles to make words from the list. Then find a science fact written in the unused letters.We have lots of non-holiday word search puzzles for students of all ages.
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